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The relation among conductance (G), spec...

The relation among conductance (G), specific conductance (K) and cell constant (l/A) is :

A

`G=k(l)/A`

B

`G=k(A)/l`

C

`Gk=l/A`

D

G=kAL

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The correct Answer is:
To find the relation among conductance (G), specific conductance (K), and cell constant (l/A), we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Definitions**: - **Conductance (G)**: It is the ability of a solution to conduct electricity and is defined as the reciprocal of resistance (R). - **Specific Conductance (K)**: It is the conductance of a solution per unit length and unit area, and is defined as the reciprocal of specific resistance (ρ). - **Cell Constant (l/A)**: It is defined as the ratio of the length of the conductor (l) to the cross-sectional area (A). 2. **Write the Formula for Resistance**: - The resistance (R) of a conductor can be expressed as: \[ R = \rho \frac{l}{A} \] where ρ is the resistivity (specific resistance), l is the length of the conductor, and A is the cross-sectional area. 3. **Relate Conductance to Resistance**: - Since conductance (G) is the reciprocal of resistance (R), we can write: \[ G = \frac{1}{R} \] 4. **Substitute the Expression for Resistance**: - By substituting the expression for R into the conductance formula, we get: \[ G = \frac{1}{\rho \frac{l}{A}} = \frac{A}{\rho l} \] 5. **Relate Specific Conductance to Specific Resistance**: - Specific conductance (K) is defined as: \[ K = \frac{1}{\rho} \] Thus, we can rewrite the expression for G in terms of K: \[ G = K \cdot \frac{A}{l} \] 6. **Final Relation**: - Rearranging the equation gives us the final relation among conductance (G), specific conductance (K), and cell constant (l/A): \[ G = K \cdot \frac{A}{l} \] ### Conclusion: The relation among conductance (G), specific conductance (K), and cell constant (l/A) is: \[ G = K \cdot \frac{A}{l} \]
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