If `X` is specific resistance of the electrolytic solution and `Y` is the molarity of the solution then molar conductivity of solution is (in `Scm^2mol^(-1)`) given by:

Options

A. `(1000X)/Y`
B. `1000(Y)/(X)`
C. `(1000)/(XY)`
D. `(XY)/(1000)`

Answer

To find the molar conductivity of an electrolytic solution given the specific resistance (X) and the molarity (Y) of the solution, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Definitions**:
- Specific resistance (X) is the resistance of the solution per unit volume.
- Molarity (Y) is the concentration of the solution in moles per liter.

2. **Relate Specific Resistance to Specific Conductance**:
- Specific conductance (K) is defined as the reciprocal of specific resistance. Therefore, we have:
\[ K = \frac{1}{X} \]

3. **Use the Formula for Molar Conductivity**:
- The formula for molar conductivity (Λm) is given by:
\[ Λ_m = K \times \frac{1000}{Y} \]
where K is the specific conductance and Y is the molarity of the solution.

4. **Substitute K into the Molar Conductivity Formula**:
- Substitute the expression for K from step 2 into the molar conductivity formula:
\[ Λ_m = \left(\frac{1}{X}\right) \times \frac{1000}{Y} \]

5. **Simplify the Expression**:
- Simplifying the above expression gives:
\[ Λ_m = \frac{1000}{XY} \]

6. **Final Result**:
- Therefore, the molar conductivity of the solution is:
\[ Λ_m = \frac{1000}{XY} \quad \text{(in } \text{S cm}^2 \text{mol}^{-1}\text{)} \]

### Conclusion:
The molar conductivity of the solution is given by:
\[ Λ_m = \frac{1000}{XY} \]