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Copper reduced NO(3)^(-) into NO and NO(...

Copper reduced `NO_(3)^(-)` into `NO` and `NO_(2)` depending upon conc.of `HNO_(3)` in solution. Assuming `[Cu^(2+)] = 0.1M`, and `P_(NO) = P_(NO_(2)) = 10^(-3)` atm and using data answer the following questions:
`E_(Cu^(2+)//Cu)^(@) =+ 0.34` volt, at `298K (RT)/(F) (2.303) = 0.06` volt
`E_(cell)` for reduction of `NO_(3)^(-) rarr NO` by `Cu(s)` when `[HNO_(3)] = 1M` is [At `t = 298]`

A

`10^(1.23)M`

B

`10^(0.56)M`

C

`10^(0.66)M`

D

`10^(0.12)M`

Text Solution

Verified by Experts

The correct Answer is:
C
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