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The reamainder left out when 8^(2n) - (6...

The reamainder left out when `8^(2n) - (62)^(2n+1)` is divided by 9 is

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`f(x) = 8^(2n) - (62)^(2n+1)`
`= (9-1)^(2n) - (9 xx 7-1)^(2n+1)`
`(1+x)^n = .^nC_0(1)^nx^0 + .^nC_1(x)^1 + ........ + .^nC_(n-1)x^(n-1) + .^nC_n x^n`
remainder= `.^(2n)C_(2n) (-1)^(2n) - .^(2n+1)C_(2n+1)(-1)^(2n+1)`
`= 1 xx 1 - 1xx(-1) = 1+1 = 2`
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