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If g(x)""=int0xcos4t"dt" , then g(x""+pi...

If `g(x)""=int0xcos4t"dt"` , then `g(x""+pi)` equals: (1) `g(x)/(g(pi)` (2) `g(x)+g(pi)` (3) `g(x)-g(pi)` (4) `g(x)dotg(pi)`

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To solve the problem, we start with the given function: \[ g(x) = \int_0^x \cos^4(t) \, dt \] We need to find \( g(x + \pi) \). ### Step 1: Write the expression for \( g(x + \pi) \) ...
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