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The integral int(1+x-1/x)e^(x+1/x)dx is...

The integral `int(1+x-1/x)e^(x+1/x)dx` is equal to (1) `(x-1)e^(x+1/x)+C` (2) `x e^(x+1/x)+C` (3) `(x+1)e^(x+1/x)+C` (4) `-x e^(x+1/x)+C`

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To solve the integral \( I = \int (1 + x - \frac{1}{x}) e^{x + \frac{1}{x}} \, dx \), we can follow these steps: ### Step 1: Rewrite the Integral We start with the integral: \[ I = \int (1 + x - \frac{1}{x}) e^{x + \frac{1}{x}} \, dx \] This can be separated into two parts: ...
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