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For three events A ,B and C ,P (Exactly ...

For three events `A ,B` and `C ,P` (Exactly one of `A` or `B` occurs) `=P` (Exactly one of `B` or `C` occurs) `=P` (Exactly one of `C` or `A` occurs) `=1/4` and `P` (All the three events occur simultaneously) `=1/6dot` Then the probability that at least one of the events occurs, is : `7/(64)` (2) `3/(16)` (3) `7/(32)` (4) `7/(16)`

A

`(3)/(16)`

B

`(7)/(32)`

C

`(7)/(16)`

D

`(7)/(64)`

Text Solution

AI Generated Solution

To solve the problem step by step, we will use the given probabilities and the properties of probability for events. ### Step 1: Define the probabilities Let: - \( P(A) = p_A \) - \( P(B) = p_B \) - \( P(C) = p_C \) - \( P(A \cap B) = p_{AB} \) ...
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