Equation of travelling wave on a stertched string of linear density `5 g // m` is y=00.3 sin (450 t - 9 x) where distance and time are measured in SI units. The tension in the string is
A
10 N
B
7.5 N
C
12.5 N
D
5 N
Text Solution
AI Generated Solution
Topper's Solved these Questions
JEE MAINS
JEE MAINS PREVIOUS YEAR ENGLISH|Exercise Chemistry|1 Videos
JEE MAIN
JEE MAINS PREVIOUS YEAR ENGLISH|Exercise All Questions|452 Videos
JEE MAINS 2020
JEE MAINS PREVIOUS YEAR ENGLISH|Exercise PHYSICS|250 Videos
Similar Questions
Explore conceptually related problems
A transverse wave propagating on a stretched string of linear density 3 xx 10^-4 kg-m^-1 is represented by the equation y=0.2 sin (1.5x+60t) Where x is in metre and t is in second. The tension in the string (in Newton) is
The linear density of a vibrating string is 1.3 xx 10^(-4) kg//m A transverse wave is propagating on the string and is described by the equation y= 0.021 sin (x + 30 t) where x and y are measured in meter and t t in second the tension in the string is :-
The linear density of a vibrating string is 10^(-4) kg//m . A transverse wave is propagating on the string, which is described by the equation y=0.02 sin (x+30t) , where x and y are in metres and time t in seconds. Then tension in the string is
A transverse periodic wave on a string with a linear mass density of 0.200 kg/m is described by the following equation y=0.05 sin (420t-21.0 x) where x and y are in metres and t is in seconds.The tension in the string is equal to :
The equation of stationary wave along a stretched string is given by y = 5 sin(pi/3 x) cos 40pi t where x and y are in centimetre and t in second. The separation between two adjacent nodes is :
A travelling wave in a stretched string is described by the equation y = A sin (kx - omegat) the maximum particle velocity is
The equation of a travelling wave on a string is y = (0.10 mm ) sin [31.4 m^(-1) x + (314s^(-1)) t]
The equation of a transverse wave travelling along a string is given by y=0.4sin[pi(0.5x-200t)] where y and x are measured in cm and t in seconds. Suppose that you clamp the string at two points L cm apart and you observe a standing wave of the same wavelength as above transverse wave. For what values of L less than 10 cm is this possible?
A transverse periodic wave ona strin with a linear mass density of 0.200kg/m is described by the following equations y=0.05sin(420t-21.0x) where x and y in metres and t is in seconds. Tension in the string is
The wave-function for a certain standing wave on a string fixed at both ends is y(x,t) = 0.5 sin (0.025pix) cos500t where x and y are in centimeters and t is seconds. The shortest possible length of the string is :
JEE MAINS PREVIOUS YEAR ENGLISH-JEE MAINS-Chemistry
