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(p to q) wedge (q to -p) is equivalent t...

`(p to q) wedge (q to -p)` is equivalent to

A

1. q

B

2. `~q`

C

3. p

D

4. `~p`

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AI Generated Solution

The correct Answer is:
To solve the problem `(p to q) wedge (q to -p)`, we need to analyze the logical expressions involved. Let's break it down step by step. ### Step 1: Understand the symbols - **p to q** (denoted as \( p \implies q \)): This is a logical implication that is false only when \( p \) is true and \( q \) is false. - **q to -p** (denoted as \( q \implies \neg p \)): This is also a logical implication that is false only when \( q \) is true and \( \neg p \) (not p) is false, which means \( p \) is true. ### Step 2: Construct the truth table We will create a truth table for \( p \), \( q \), \( p \implies q \), \( \neg p \), and \( q \implies \neg p \). | p | q | \( p \implies q \) | \( \neg p \) | \( q \implies \neg p \) | |-------|-------|---------------------|---------------|--------------------------| | T | T | T | F | F | | T | F | F | F | F | | F | T | T | T | T | | F | F | T | T | T | ### Step 3: Evaluate \( (p \implies q) \wedge (q \implies \neg p) \) Now we will evaluate the conjunction of \( p \implies q \) and \( q \implies \neg p \). | p | q | \( p \implies q \) | \( q \implies \neg p \) | \( (p \implies q) \wedge (q \implies \neg p) \) | |-------|-------|---------------------|--------------------------|--------------------------------------------------| | T | T | T | F | F | | T | F | F | F | F | | F | T | T | T | T | | F | F | T | T | T | ### Step 4: Analyze the results From the truth table for \( (p \implies q) \wedge (q \implies \neg p) \), we see that the expression is true when: - \( p = F \) and \( q = T \) - \( p = F \) and \( q = F \) This corresponds to the truth values of \( \neg p \): - When \( p = F \), \( \neg p = T \). - When \( p = T \), \( \neg p = F \). ### Step 5: Conclusion The final truth table for \( (p \implies q) \wedge (q \implies \neg p) \) matches the truth table for \( \neg p \). Therefore, we conclude that: **The expression \( (p \implies q) \wedge (q \implies \neg p) \) is equivalent to \( \neg p \).** ### Final Answer The equivalent expression is \( \neg p \). ---
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