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If lim(x rarr 0)x[4/x]= A, then the valu...

If `lim_(x rarr 0)x[4/x]= A`, then the value of x at which `f(x) = [x^2]sinpix` is discontinuous , (where `[.]` denotes greatest integer function)

A

`sqrt(A+1)`

B

`sqrt(A+5)`

C

`sqrt(A)`

D

`sqrt(A+21)`

Text Solution

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The correct Answer is:
To solve the problem, we need to analyze the limit and the function given in the question step by step. ### Step 1: Evaluate the limit We start with the limit: \[ \lim_{x \to 0} x \left[ \frac{4}{x} \right] \] Here, \([ \cdot ]\) denotes the greatest integer function. We can rewrite this as: \[ \lim_{x \to 0} x \left( \frac{4}{x} - \left\{ \frac{4}{x} \right\} \right) \] where \(\{ \cdot \}\) denotes the fractional part of the number. ### Step 2: Simplify the limit expression This can be simplified to: \[ \lim_{x \to 0} (4 - x \left\{ \frac{4}{x} \right\}) \] As \(x\) approaches 0, \(\left\{ \frac{4}{x} \right\}\) oscillates between 0 and 1, but it remains bounded. Thus, \(x \left\{ \frac{4}{x} \right\}\) approaches 0. ### Step 3: Calculate the limit Therefore, we have: \[ \lim_{x \to 0} (4 - x \left\{ \frac{4}{x} \right\}) = 4 - 0 = 4 \] Thus, we find that: \[ A = 4 \] ### Step 4: Analyze the function \(f(x)\) Now we need to find the points of discontinuity of the function: \[ f(x) = \left[ x^2 \sin(\pi x) \right] \] The function \(\left[ x^2 \sin(\pi x) \right]\) will be discontinuous at points where \(x^2 \sin(\pi x)\) is an integer. ### Step 5: Identify points of discontinuity The function \(\sin(\pi x)\) is 0 at integer values of \(x\). Therefore, \(f(x)\) will be discontinuous at integer values of \(x\) because: - At integers, \(x^2 \sin(\pi x) = 0\), which is an integer. - The greatest integer function \([x^2 \sin(\pi x)]\) will jump at these points. ### Step 6: Check for irrational points Additionally, \(f(x)\) could also be discontinuous at points where \(x^2\) is an integer (i.e., \(x = \sqrt{n}\) for integers \(n\)). However, since we are primarily looking for discontinuities related to the greatest integer function, we focus on the integers. ### Conclusion The function \(f(x)\) is discontinuous at all integer values of \(x\).
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