The displacement x of a particle varies with time t as
`x=4t^(2)-15t+25`
Find the position, velocity and acceleration of the particle at t=0. When will the velocity of the particle become zero? Can we call the motion of the particle as one with uniform acceleration ?

The displacement s of a particle at a time t is given bys =t^(3)-4t^(2)-5t. Find its velocity and acceleration at t=2 .

The displacement x of a particle varies as sqrt(x)=t-2 (i) What is the velocity and acceleration of the particle at t=0? (ii) When will the velocity of the particle become zero? (iii) What is the displacement of the particle when its velocity is zero? (iv) Is the motion of the particle uniformly accelerated or not?

the angular velocity omega of a particle varies with time t as omega = 5t^2 + 25 rad/s . the angular acceleration of the particle at t=1 s is

The position x of a particle varies with time t as x=at^(2)-bt^(3) .The acceleration of the particle will be zero at time t equal to

The position x of a particle varies with time t as x=At^(2)-Bt^(3) .the acceleration at time t of the particle will be equal to zero

The position x of a particle varies with time t as x=a t^(2)-b . For what value of t acceleration is zero?

The velocity time relation of a particle is given by v = (3t^(2) -2t-1) m//s Calculate the position and acceleration of the particle when velocity of the particle is zero . Given the initial position of the particle is 5m .

Figure gives the x-t plot of a particle is one dimensional motion. Give the signs of position, velocity and acceleration of the particle at t = 0.3s

The position x of a particle varies with time t as X=at^(2)-bt^(3).The acceleration of the particle will be zero at time (t) equal to