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The length of a suspended loire increase...

The length of a suspended loire increases by `10^-4` of its original length when a stress of `10^7 Nm^-2` is applied on it. Calculate the Young's modulus of the material of the wire.

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Knowledge Check

  • A wire suspended vertically from one of its ends is stretched by attaching a weight of 20 N to its lower end. If its length changes by 1% and if the Young's modulus of the material of the wire is 2 xx 10^(11) N//m^(2) , then the area of cross section of the wire is

    A
    `1 mm^(2)`
    B
    `10^(-1) mm^(2)`
    C
    `10^(-2) mm^(2)`
    D
    `10^(-3) mm^(2)`

  • A load of 4 kg is suspended from a ceiling through a steel wire of length 20 m and radius 2 mm . It is found that the length of the wire increases by 0.031 mm , as equilibrium is achieved. If g = 3.1xxpi ms(-2) , the value of young's modulus of the material of the wire (in Nm^(-2)) is

    A
    (A) `2xx10^(12)`
    B
    (B) `4xx10^(11)`
    C
    (C) `2xx10^(11)`
    D
    (D) `0.02xx10^(9)`

  • When a wire is stretched by a force the strain produced in the wire is 2 xx 10^(-4) . If the energy stored per unit volume of the wire is 4 xx 10^(4) "joule"//m^(3) then the Young's modulus of the material of the wire will be,

    A
    `1 xx 10^(12) N//m^(2)`
    B
    `1.5 xx 10^(12) N//m^(2)`
    C
    `2 xx 10^(12) N//m^(2)`
    D
    `2.5 xx 10^(12) N//m^(2)`

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