The displacement x of a particle is dependent on time t according to the relation : `x = 3 - 5t + 2t^(2)`. If t is measured in seconds and s in metres, find its velocity at t = 2s.

The displacement x of a particle is dependent on time t according to the relation : x = 3 - 5t + 2t^(2) . If t is measured in seconds and s in metres, find its acceleration at t = 4s.

The displacement (x) of particle depends on time (t) as x = alpha t^(2) - beta t^(3) .

The position x of a particle varies with time t according to the relation x=t^3+3t^2+2t . Find the velocity and acceleration as functions of time.

If the displacement x of a particle (in metre) is related with time (in second) according to relation x = 2 t^3 - 3t^2 +2 t + 2 find the position, velocity and acceleration of a particle at the end of 2 seconds.

The displacement of a particle is described by x = t + 2t^(2) +3t^(3) -4t^(4) The acceleration at t = 3s is

The displacement of a particle moving in a straight line is described by the relation s=6+12t-2t^(2) . Here s is in metre and t in second. The distance covered by the particle in first 5s is

The displacement of a particle is represented by the equation, s=3 t^3 =7 t^2 +4 t+8 where (s) is in metres and (t) in seconds . The acceleration of the particle at t=1 s is.

The position of a particle varies with time according to the relation x=3t^(2)+5t^(3)+7t , where x is in m and t is in s. Find (i) Displacement during time interval t = 1 s to t = 3 s. (ii) Average velocity during time interval 0 - 5 s. (iii) Instantaneous velocity at t = 0 and t = 5 s. (iv) Average acceleration during time interval 0 - 5 s. (v) Acceleration at t = 0 and t = 5 s.

The position of a particle is given by the equation f(t)=t^(3)-6t^(2)+9t where t is measured in second and s in meter. Find the acceleration at time t. What is the acceleration at 4 s?