A bus starts from rest with a constant acceleration of `5 m//s^(2)` at the same time a car travelling with a constant velocity `50 m//s` over takes and passes the bus. How fast is the bus travelling when they are side by side?

A bus starts from rest with constant acceleration of 5 ms^–2 . At the same time a car travelling with a constant velocity of 50 ms^–1 overtakes and passes the bus. (i) Find at what distance will the bus overtake the car ? (ii) How fast will the bus be travelling then ?

A bus starts from rest and moves with constant acceleration 8 m//s^(2) . At the same time, a car traveling with a constant velocity 16 m//s overtakes and passes the bus. After how much time and at what distance the bus overtakes the car?

At the insutant the traffic light turns green a car starts with a constant acc. 2 m//s^(2) . At the same instant a truck, travelling with a constant speed of 10 m//s , overtakes and passes the car. (a) How far beyond the starting point will the car overtake the truck ? (b) How fast will the car be travelling at that instant? (c) Draw s//t curves for each vehicle.

A body starting from rest has an acceleration of 5m//s^(2) . Calculate the distance travelled by it in 4^(th) second.

A body starting from rest and has uniform acceleration 8 m//s^(2) . The distance travelled by it in 5^(th) second will be

A body starting from rest is moving with a uniform acceleration of 8m/s^(2) . Then the distance travelled by it in 5th second will be

A car travels half the distance with a constant velocity of 40 m//s and the remaining half with a constant velocity of 60 m//s . The average velocity of the car in m//s is

A man is 25 m behind a bus, when bus starts accelerating at 2 ms^(-2) and man starts moving with constant velocity of 10 ms^(-1) . Time taken by him to board the bus is

A student is running at her top speed of 5.0 m s^(-1) , to catch a bus, which is stopped at the bus stop. When the student is still 40.0m from the bus, it starts to pull away, moving with a constant acceleration of 0.2 m s^(-2) . a For how much time and what distance does the student have to run at 5.0 m s^(-1) before she overtakes the bus? b. When she reached the bus, how fast was the bus travelling? c. Sketch an x-t graph for bothe the student and the bus. d. Teh equations uou used in part (a)to find the time have a second solution, corresponding to a later time for which the student and the bus are again at thesame place if they continue their specified motions. Explain the significance of this second solution. How fast is the bus travelling at this point? e. If the student s top speed is 3.5 m s^(-1), will she catch the bus? f. What is the minimum speed the student must have to just catch up with the bus?For what time and what distance dies she have to run in that case?