Can we use equations of kinematics to find the height attained by a body projected upwares with any velocity ?

What are the factors on which the maximum height attained by a body thrown upwards depends?

Can we use the equation v = u + at in SHM or not ?

What is the maximum height attained by a body projected with a velocity equal to one- third of the escape velocity from the surface of the earth? (Radius of the earth=R)

If the horizontal range of a projectile be a and the maximum height attained by it is b, then prove that the velocity of projection is

A body is projected vertically upwards from the surface of the earth with a velocity equal to half of escape velocity of the earth. If R is radius of the earth, maximum height attained by the body from the surface of the earth is

If the horizontal range of projectile be (a) and the maximum height attained by it is (b) then prove that the velocity of projection is [ 2 g (b+ a^2 /(16 b)) ] ^(1//2) .

Two stones are projected so as to reach the same distance from the point of projection on a horizontal surface. The maximum height reached by one exceeds thr other by an amount equal to half the sum of the height attained by them. Then angle of projection of the stone which attains smaller height is

Maximum height attained from the point of projection is:

A body of mass m is from surface of the earth projected vertically upwards with a velocity such that it rises to a height of 20 m. If the same body is projected with same velocity from a planet density is (1)/(4) th of density of earth and radius is (1)/(2) of that of Earth, then find the height to which the body will rise on the planet.