A body is released from the top of a tower of height h. It takes t sec to reach the ground. Where will be the ball after time `(t)/(2)` sec?

A ball is released from the top of a tower of height h metre. It takes T second to reach the ground. What is the position of the ball in T/3 second?

A ball is relased from the top of a building 180m high. It takes time t to reach the ground With what speed should it be projected down so that it reaches the ground time (51)/(6) .

A body released from the top of a tower falls through half the height of tower in 3 seconds. If will reach the ground after nearly .

The balls are released from the top of a tower of height H at regular interval of time. When first ball reaches at the ground, the n^(th) ball is to be just released and ((n+1)/(2))^(th) ball is at same distance 'h' from top of the tower. The value of h is

A ball is released from the top of a tower of height H m . After 2 s is stopped and then instantaneously released. What will be its heitht after next 2 s ?.

A ball is thrown vertically upwards from the top of tower of height h with velocity v . The ball strikes the ground after time.