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Matching type Question : For a body thro...

Matching type Question : For a body thrown vertically upwards with initial velocity u

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At time t=0 a body is thrown vertically upwards with a velocity "50m/sec" .At time t=2 sec another body is thrown vertically upwards with the same velocity "50m/sec" .the two bodies will meet at time__ sec (a=10m/sec^(2))

Calculate the maximum height attained by the body thrown vertically upward with a velocity of 9.8m//s (g=9.8m//s^2)

Knowledge Check

  • Question Stimulus A stone is thrown vertically upwards with an initial velocity of 30 ms^(-1) . Acceleration due to gravity g = 10 ms^(-2) . The maximum height reached by the stone is

    A
    30 m
    B
    4.5 m
    C
    45 m
    D
    90 m

  • The velocity-time graph of a stone thrown vertically upward with an initial velocity of 30ms^(-1) is shown in the figure. The velocity in the upward direction is taken as positive and that in the downward direction as negative. What is the maximum height to which the stone rises?

    A
    30 m
    B
    45 m
    C
    60 m
    D
    90 m

  • Velocity-time graph of a body thrown vertically up is

    A
    a straight line
    B
    a parabola
    C
    a hyperbola
    D
    circle

    • Similar Questions

    Explore conceptually related problems

    A body of mass 2 kg is thrown vertically upwards with an initial velocity of 20 m/s. What will be its potential energy at the end of 2 s ? (Assume g = 10 m//s^(2) ).

    A particle is thrown vertically upward with a velocity of u. Find its time of flight.

    A body is projected with the velocity u_(1) from the point A as shown in Figure. At the same time another body is projectd vertically upwards with the velocity u_(2) from the point B. What shold be the value of (u_(1))/(u_(2)) for both the bodies to collide.

    Velocity-time curve for a body projected vertically upwards is

    A stone is thrown vertically upwards with an initial velocity u from the top of a tower of lieight (12u^(2))/(g) With what velocity does the stone reach the ground?

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