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Derive the equations of motion given bel...

Derive the equations of motion given below: v=u+at

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Derive the equations of motion for an object in uniformly accelerated motion in one dimension using calculus.

Derive the following equations of motion for uniformly accelerated motion from velocity-time graph : v^(2) - u^(2) = 2as

Knowledge Check

  • The equation of motion may be given by

    A
    `x=+-Asin(sqrt(b/a))`t
    B
    `x=+-Acos(sqrt(b/a))t`
    C
    `x=+-Asin(sqrt(b/a)t+theta)` where `theta=pi/2`
    D
    None of the above.

  • The equation of the graph given below is

    A
    `Y=4`
    B
    `X=4`
    C
    `X=-4`
    D
    `Y=0`

  • An object is moving with uniform acceleration a. Its initial velocity is u and after time t its velocity is v. The equation of its motion is v = u + at. The velocity (along y-axis) time (along x-axis) graph shall be a straight line

    A
    passing through origin
    B
    with x-intercept u
    C
    with y-intercept u
    D
    with slope u

    • Similar Questions

    Explore conceptually related problems

    For uniform accelerated motion, draw by graphical method establish the following equations of motion : v = u + at

    Derive the following equations of motion for an object moving with constant acceleration along a straight line : s_nth = v_0 + a/2 (2n-1) .

    Derive the following equations of motion for an object moving with constant acceleration along a straight line : v^(2) = v_0^(2) + 2a(x - x_0) = v_0^(2) + 2as

    Derive the following equations of motion for uniformly accelerated motion from velocity-time graph : s = ut + 1/2 at^(2)

    Write and derive all the three equations of motion analytically.

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