Under a force of 10 hati - 3 hatj +6 hat...

Under a force of `10 hati - 3 hatj +6 hatk` newton, a body of mass 5 kg is displaced from the position `6 hati + 5 hatj - 3 hatk` to the position `10 hati - 2hatj + 7 hatk`. Calculate the work done.

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Under a force ( 10 hati - 3 hatj + 6 hatk) newton a body of mass 5 kg moves from position ( 6 hati + 5 hatj - 3 hatk) m to position ( 10 hati - 2hatj+ 7hatk) m . Deduce the work done.

Under the effect of a force vecF=5hati-2 hatj+3hatk N, abody of mass 1 kg is displaced from position 5hati+4hatj-2hatk to position 8hati-hatj-hat4k . Calculate the work done .

Under a fore (10hati-3hatj+6hatk) newton a bod of mass 5 kg moves from position (6hati+5hatj-3hatk) m to position (10hati-2hatj+7hatk) m. deduce the work done.

A uniform force of (3 hati + hatj) newton acts on a partical of mass 2 kg . Hence the partical is displaced from position (2 hati + hatk) metre to possion (4 hati + 3 hatj - hatk) meters. The work done by the force on the partical is

Two constant forces F_(1)=2hati-3hatj+3hatk(N) and F_(2)=hati+hatj-2hatk(N) act on a body and displace it from the position r_(1)=hati+2hatj-2hatk(m) to the position r_(2)=7hati+10hatj+5hatk(m) . What is the work done

Two constat forece vecF_(1) = (2hati + 3hatj + 3hatk) newton and vecF_(2) = (5hati - 6hatj - 2hatk) newton act toghter on a particle during its displacement from the position (20hati + 15hatj) m to 8vecKm . Calculate the work done.

A particle is acted upon by constant forces 4hati +hatj - 3hatk and 3hati + hatj -hatk which displace it from a point hati + 2hatj + 3hatk to the point 5hati + 4hatj + hatk . The work done in standard units by the forces is given by:

The points with position vectors 5hati + 5hatk, -4hati + 3hatj - hatk and 2hati +hatj + 3hatk

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