In between two hills of heights 100 m and 92 m respectively, there is a valley of breadth 16 m.Vehicle was initally at rest. If a vehicle jumps from the first hill to the second, what must be its minimum horizontal velocity so that it may not fall into the valley ? Take `g = 9 ms^-2`.

Two hills of height 100 m and 80 m have a valley of breadth 15 between them . A stunt diver jumps from the first hill to the second hill . Calculate his minimum horizontal velocity so that he may not fall into the vailly . Take g=10ms^(-2) .

Two cliffs of heights 120 m and 100.4 m are separated bya horizontal distance of 16 m if a car has to reach from the first cliff to the second the horizontal velocity of car should be

The maximum range of a gun from horizontal terms is 16 km If g = 10 m//s^(2) what must be the muzele velocity of the sheet?

Two bodies begin a free fall from rest from the same height 2 seconds apart. How long after the first body begins to fall, the two bodies will be 40 m apart? ("Take g = 10ms"^(-2))

A spherical ball of mass 2 kg is stationalry at the top of a hill of height 100 m. It rolls down a smooth surface to the ground, then cilimbs up another hill of height 30 m and finally rolls down on a smooth surface to a horizontal base at a height of 20 m abvoe the ground. What is the final velocity attained by the ball? (g=10m//s^(2))

Two diamonds begin a free fall from rest from the same height, 1.0 s apart. How long after the first diamond begins to fall will the two diamonds be 10 m apart? Take g = 10 m//s^2.

What are the angles of projection of a projectile projected with velocity 30 ms^(-1) , so that the horizontal range is 45 m ? Take g = 10 ms^(-2) .

A person sees an object on a tree at a heitht of 40 m and at a distance of 60 m . Whith what velocity he showld throw an arrow at an angle of 45^@ so that it may hit the object ? Take g= 10 ms^(2) .