A boy playing on the roof of a 10 m high building throws a ball with a speed of 10 m/s at an angle ` 30 ^@ ` with the horizontal. How far from the throwing point will the ball be at the height of 10 m from the ground?
` (g = 10 m//s ^ 2 ) `

A boy playing on the roof of a 10 m high building throws a ball with a speed of 10 m//s^(-1) at an angle of 30^(@) with the horizontal. How far from the throwing point will the ball be at a height of 10 m from the ground?

A boy playing on the roof of a 10 m high building throws a ball with a speed of 10 m//s at an angle of 30(@) with the horizontal. How far from the throwing point will the ball be at the height of 10 m from the ground ? [ g = 10m//s^(2) , sin 30^(@) = (1)/(2) , cos 30^(@) = (sqrt(3))/(2)]

A boy playing on the roof of a 10 m high building throws a ball with a speed of 10 ms^-1 at an angle of 30^0 with the horizontal. How far from the throwing point will the ball be at the height of 10 m from the ground?given that g=10 ms^-2 , sin30^0=1/2 , cos30^0=sqrt3/2

A ball is thrown from the ground with a velocity of 20sqrt3 m/s making an angle of 60^@ with the horizontal. The ball will be at a height of 40 m from the ground after a time t equal to (g=10 ms^(-2))

A ball is thrown at a speed of 40 m/s at an angle of 60^0 with the horizontal. Find a. the maximum height reached and b. the range of te ball. Take g=10 m/s^2 .

A football player throws a ball with a velocity of 50 metre/sec at an angle 30 degrees from the horizontal. The ball remains in the air for (g = 10m//s^(2))

A ball is projected from ground with a speed of 20ms^(-1) at an angle of 45^(@) with horizontal.There is a wall of 25m height at a distance of 10m from the projection point. The ball will hit the wall at a height of

A ball is projected upwards from the top of a tower with a velocity 50ms^-1 making an angle 30^@ with the horizontal. The height of tower is 70m. After how many seconds from the instant of throwing, will the ball reach the ground. (g=10 ms^-2)

A particle is projected with velocity of 10m/s at an angle of 15° with horizontal.The horizontal range will be (g = 10m/s^2)