If the resultant of two vectors `vec P` and `vec Q` is given by `R^(2) = P^(2) + Q^(2)`, then the angle between the vectors `vec P` and `vec Q` is _____.

If |vec P xx vec Q|=PQ then the angle between vec P and vec Q is

What is the anlge between vec P xx vec Q and vec Q xx vec P is

Given vec(p)*(vec(P)+vec(Q))=P^(2) then the angle between vec(P)andvec(Q) is

If vec(P).vec(Q)= PQ , then angle between vec(P) and vec(Q) is

Find the angle between two vectors vec P and vec Q if resultant of the vectors is given by R^2 = P^2 + Q^2 .

The resultant of two vectors vec(P) and vec(Q) is vec(R) . If vec(Q) is doubled then the new resultant vector is perpendicular to vec(P) . Then magnitude of vec(R) is :-

If |vec(P) + vec(Q)| = |vec(P) - vec(Q)| , find the angle between vec(P) and vec(Q) .

The resultant of two vectors vec(P) and vec(Q) is vec(R ) . If the magnitude of vec(Q) is doubled, the new resultant vector becomes perpendicular to vec(P) . Then, the magnitude of vec(R ) is equal to

The greatest resultant of two vectors vec P and vec Q is (n) times their least reast resultant. Fiven | vec P | gt |vec Q| . When theta is the angle between the two vectors, their resultant is half the sum of the two vectors. Show that, cos theta =- (n^(2) +2) // (n n^(2) -1) .

The sum of two forces vec P and vec Q is vec R such that |vec R|=|vec P| .The angle theta (in degrees) that the resultant of 2vec P and vec Q will make with vec Q is