A projectile fired from the ground follows a parabolic path. The speed of the projectile is minimum at the top of its path.

The pathe of a projectile is

If upsilon_(e) is the escape velocity for earth when a projectile is fired from the surface of earth. Then, the escape velocity if the same projectile is fired from its centre is

A projectile is fired from the origin with a velocity v_(0) at an angle theta with x-axis. The speed of the projectile at an altitude h is .

Prove that: The path of a projectile is a straight line.

A path followed by a projectile is as shown. The angle of projection is?

Particle A is projected with speed u at an angle theta with the horizontal . Another particle B is also projected with same speed u at an angle 90-theta with the horizontal . Both the projectiles are fired from the ground and reaches the ground after completing the projectile . Time of flight for A is t_(A) and that for B it is t_(B) . Range of the projectile A is R_(A) and that for B is R_(B) . Maximum height reached by the projectile A is h_(A) and that for B is h_(B)

Why does a projectile fired along the horizontal not follow a straight line path ?

If a satellite performs parabolic path, then