For a projectile first with velocity u at an angle `theta` with the horizontal.

A projectile is thrown with velocity v at an angle theta with the horizontal. When the projectile is at a height equal to half of the maximum height,. The vertical component of the velocity of projectile is.

A projectile is thrown with velocity v at an angle theta with the horizontal. When the projectile is at a height equal to half of the maximum height,. The velocity of the projectile when it is at a height equal to half of the maximum height is.

A projectile is projected with a velocity u at an angle theta with the horizontal. For a fixed theta , which of the graphs shown in the following figure shows the variation of range R versus u?

A projectile is thrown with velocity u making an angle theta with the horizontal. Its time of flight on the horizontal ground is 4 second. The projectile is moving at angle of 45^(@) with the horizontal just one second after the projection. Hence the angle theta is (take g=10m//s^(2) )

The angle of which the velocity vector of a projectile thrown with a velocity u at an angle theta to the horizontal will take with the horizontal after time t of its being thrown up is

A projectile is thrown with a velocity u_(0) at an angle theta with the horizontal. The ratio of the rate of change of speed w.r.t. time, at highest point to that at the point of projection, is

A projectile is fired with a velocity 'u' making an angle theta with the horizontal. Show that its trajectory is a parabola.