Acceleration of a particle under projectile motion at the highest point of its trajectory is :

A particle is projected at angle theta with horizontal with velocity v_0 at t = 0 . Find (a) tangential and normal acceleration of the particle at t = 0 and at highest point of its trajectory. (b) the radius of curvature att = 0 and highest point. .

A projectile of mass m is launched with an initial velocity vec v_i making an angle theta with the horizontal as shown in figure. The projectile momentum of the particle about the origin when it is at the highest point of its trajectory is. .

The kinetic energy of a projectile at the highest point is-

Average velocity of a particle in projectile motion between its starting point and the highest point of its trajectory is (projectin speed = u, angle projection from horizontal = theta )

A particle of mass m is thrown with speed v_(0) at angle 30^(@) with horizontal. Find the angular momentum about the point of projection when the particle is at the highest point of its trajectory.

Motion Of A Particle Under Gravity

A particle is projected from the ground with an initial speed v at an angle theta with horizontal. The average velocity of the particle between its point of projection and highest point of trajectory is [EAM 2013]

A javelin thrown into air at an angle with the horizontal has a range of 200 m. If the time of flight is 5 second, then the horizontal component of velocity of the projectile at the highest point of the trajectory is

A particle of mass m is projected with velocity v at an angle theta with the horizontal. Find its angular momentum about the point of projection when it is at the highest point of its trajectory.

The projectile has only vertical component of velocity at the highest point of its trajectory. At the highest point, only one component of velocity is present.