A projectile is fired with a velocity 'u' making an angle `theta` with the horizontal. Show that its trajectory is a parabola.

For a projectile first with velocity u at an angle theta with the horizontal.

A projectile is fired at an angle theta with horizontal. (a) Show that its trajectory is a parabola (b) Prove that for a given velocity of projection the horizontal range is same for (90^(@)-theta) (c) Obtain an expression for velocity of projectile at any instant.

A particle is projected with a velocity u making an angle theta with the horizontal. At any instant its velocity becomes v which is perpendicular to the initial velocity u. Then v is

A particle is fired with velocity u making angle theta with the horizontal.What is the change in velocity when it is at the highest point?

A projectile is projected with a velocity u at an angle theta with the horizontal. For a fixed theta , which of the graphs shown in the following figure shows the variation of range R versus u?

A projectile is thrown with velocity u making an angle theta with the horizontal. Its time of flight on the horizontal ground is 4 second. The projectile is moving at angle of 45^(@) with the horizontal just one second after the projection. Hence the angle theta is (take g=10m//s^(2) )

A particle is projected with a velocity u making an angle theta with the horizontal. The instantaneous power of the gravitational force

A particle is projeced with a velocity u making an angle theta with the horizontal. The instantaneous power of the gravitational force