A projectile is projected with velocity `u` making angle `theta` with horizontal direction, find : horizontal range.

A projectile is projected with velocity u making angle theta with horizontal direction, find : time of flight.

Whe a projectile is projeected with velcity (v0 making an angle theta with the horizontal direction, then maximum horizontal range is…………………………… .

For a projectile first with velocity u at an angle theta with the horizontal.

A projectile is thrown with velocity u making an angle theta with the horizontal. Its time of flight on the horizontal ground is 4 second. The projectile is moving at angle of 45^(@) with the horizontal just one second after the projection. Hence the angle theta is (take g=10m//s^(2) )

Find (a) time of flight , (b) Max.height (c ) Horizontal range of projectile projected with speed (v) making an angle theta with the horizontal direction from ground.

A projectile is projected with a velocity u at an angle theta with the horizontal. For a fixed theta , which of the graphs shown in the following figure shows the variation of range R versus u?

A projectile is projected from horizontal with velocity (u) making an angle 45^(@) with the horizontal direction. Find the distance of the highest point of the projectile from its starting point.

A particle is projected with a velocity u making an angle theta with the horizontal. At any instant its velocity becomes v which is perpendicular to the initial velocity u. Then v is

A particle is projected from the ground with velocity u at angle theta with horizontal.The horizontal range,maximum height and time of flight are R,H and T respectively.Now keeping u as fixed, theta is varied from 30^(@) to 60^(@) .Then

A particle is projected with a velocity u making an angle theta with the horizontal. The instantaneous power of the gravitational force