Show that the horizontalrange is same for a projectile whether `theta` is the angle of projection with the horizontal or with the vertical.

Show that there are two angles of projection for which the horizontal range is the same.

In the following questions a statement of assertion (A) is followed by a statement of reason ( R). A: Horizontal range of a projectile is always same for angle of projection theta with horizontal or theta with vertical . R : Horizontal range depends only on angle of projection .

The horizontal range and the maximum height of a projectile are equal. The angle of projection of the projectile is

For a projectile first with velocity u at an angle theta with the horizontal.

Statement-1 : A man projects a stone with speed u at some angle. He again projects a stone with same speed such that time of flight now is different. The horizontal ranges in both the cases may be same. (Neglect air friction) Statement-2 : The horizontal range is same for two projectiles projected with same speed if one is projected at an angle q with the horizontal and other is projected at an angle (90^(@) theta) with the horizontal. (Neglect air friction)

Show that the horizontal range of a projectile is same for two angles of projection . Is the sum of maximum heights for these two angles dependent on the angle of projectile ?

The horizontal range is equal to two times maximum height of a projectile. The angle of projection ofthe projectile is:

The horizontal range is four times the maximum height attained by a projectile. The angle of projection is

A projectile is thrown with velocity u making an angle theta with the horizontal. Its time of flight on the horizontal ground is 4 second. The projectile is moving at angle of 45^(@) with the horizontal just one second after the projection. Hence the angle theta is (take g=10m//s^(2) )