Assertion: Horizontal range is same for angle of projection `theta and (90^(@)- theta)`.
Reason : Horizontal range is independent of angle of projection.

In the following questions a statement of assertion (A) is followed by a statement of reason ( R). A: Horizontal range of a projectile is always same for angle of projection theta with horizontal or theta with vertical . R : Horizontal range depends only on angle of projection .

Show that the horizontal range is maximum when the angle of projection is 45^(@)

There are two angles of projection for which the horizontal range is the same. Show that the sum of the maximum heights for these two angles is independent of the angle of projection.

Show that the horizontal range of a projectile is same for two angles of projection . Is the sum of maximum heights for these two angles dependent on the angle of projectile ?

A ball projected with a velocity of 28m/sec has a horizontal range 40m. Find the two angles of projection.

The question given below consist of an assertion and the reason . Use the following key to choose appropriate answer: Assertion: Range of projectile motion is same when particle is projected at an angle theta with the horizontal or at an angle (90^(@) -theta) with the horizontal . Reason : Range of projectile motion depended only on the angle of projection.

Two particles are projected with same speed but at angles of projection (45^(@)-theta) and (45^(@)+theta) . Then their horizontal ranges are in the ratio of

Galileo writes that for angles of projection of a projectile at angles (45 + theta) and (45 - theta) , the horizontal ranges described by the projectile are in the ratio of (if theta le 45 )

Assertion: In projectile motion, when horizontal range is n times the maximum height, the angle of projection is given by tan theta=(4)/(n) Reason: In the case of horizontal projection the vertical increases with time.