Find the angle of projection of a projectile for which the horizontal range and maximum height are equal.

Find the angle of projection of a porjectile for which for horizontal range and maximum height are equal.

Find the angle of projection for which the horizontal range and the maximum height are equal.

The angle of projection at which the horizontal range and maximum height of projectile are equal is

Find the angle of projection at which horizontal range and maximum height are equal.

Find the angle of projection for a projectile motion whose rang R is (n) time the maximum height H .

A body is thrown at an angle alpha to the horizontal with initial velocity v_0 .Assuming air drag to be negligible , find (i)the time of motion, (ii)maximum height of ascent and the horizontal range, (iii)the angle of projection at which they are equal , (iv)the angle of projection at which the horizontal range is maximum and the angle at which the vertical range is maximum.

For given value of u, there are two angles of projection for which the horizontal range is the same. the sum of the maximum heights for these two angles is

Assertion: For projection angle tan^(-1)(4) , the horizontal range and the maximum height of a projectile are equal. Reason: The maximum range of projectile is directely proportional to square of velocity and inversely proportional to acceleration due to gravity.

If the angle of projection theta corresponds to horizontal range being equal to the maximum height then tantheta equals :