A motor car running at the rate of `7ms^(1)` can be stooped by applying brakes in `10m` Show that total resistance to the motion when brakes are on is one fourth of the weight of the car .

A one-ton car moves with a constant velocity of 15 ms^(–1) on a rough horizontal road. The total resistance to the motion of the car is 12% of the weight of the car. The power required to keep the car moving with the same constant velocity of 15ms^(–1) is [Take g=10ms^(-2) ]

A car moving with a speed of 40 km//h can be stopped by applying the brakes after at least 2 m. If the same car is moving with a speed of 80 km//h , what is the minimum stopping distance?

A car moving at 40 km/h is tobe stopped by applyin brakes in the next 4.0 m. If the car weighs 2000 kg, what average force must be applied on it?

A motor car of mass 20 quintal moving with velocity of 60 kmh^(-1) , by the application of brakes, is brought to rest in a distance of 3 km. Find the average force of resistance in newton.

A motor car moving with a uniform speed of 20 m/sec comes to stop on the application of brakes after travelling a distance of 10m, its deceleration is

A motor car moving with a uniform speed of 20 m//sec comes to stop on the application of brakes after travelling a distance of 10m Its acceleration is

A car was movig at a rate of 18 kmh^(-1) . When the brakes were applied, it comes to rest in a distance of 100 m. Calculate the retardation produced by the brakes.