Find the apparent weight of a man weighing 49 kg on earth when he is standing in a lift which is falling freely under the action of gravity.

Find the appared weight of a man weighing 49 kg on earth, when he is standing in a lift which is (i) rising with an acceleration of 1.2 m//s^(2) (ii) going down with same acceleration (iii) falling freely under gravity (iv) going up or down with unifrom velocity . Take g= 9.8 m//s^(2) . \

The apparent weight of a body , weighing M kg wt , during free fall is

Find the pressure exerted by a man weighing 90 kg on the ground. When he is standing on one of his feet having an area of 90 cm^2 .

The apparent weight of man in a lift is less the real weight when :

A man of mass 70kg stands on a weighing scale in a lift which is moving:

Assertion: The apparent weight of a person standing in a lift which moves upwards with uniform acceleration is always higher than his true weight. Reason: The weight (on the earth surface) always acts downwards.

When an object falls freely to the earth , the force of gravity is

A man of weight W is standing on a lift which is moving upward with an acceleration a. The apparent weight of the man is

Discuss the apparent weight of a man in a lift when (i) kift is moving upwards with a constant speed (ii) lift is accelerated uniformly downwards .

A man of mass m is standing on the floor of a lift. Find his apparent weight when the lift falling freely. Take acceleration due to gravity equal to g.