Find the power of an engine which can maintain speed of `50ms^(-1)` for a train of mass `3xx10^(5)`kg on a rough line. The coefficient of friction is `0.05`. Take `g=10ms^(-2)`

An engine of power 58.8 k W pulls a train of mass 2xx10^(5)kg with a velocity of 36 kmh^(-1) . The coefficient of static friction is

A body is rolling on the ground with a velocity of 1ms^(-1) . After travelling a distance of 5 m, it comes to rest. Find the coefficient of friction. Take g=10ms^(-2) .

A crane lifts a mass of 100 kg to a height of 10m in 20s . The power of the crane is (Take g = 10 ms^(-2))

A particle of mass 0.1kg has an iniital speed of 4ms^(-1) at a point A on a roudh horizontal road. The coefficient of friction between the object and road is 0.15. The particle moves to a point B at a distance of 2m from A. What is the speed of particle at B ? Take g=10ms^(-2)

Find the power of an engine which can draw a train of 400 metric ton up the inclined plane of 1 in 98 at the rate 10 ms^(-1) . The resistance due to friction acting on the train is 10 N per ton.

Find the maximum speed at which a car can take turn round a curve of 30 cm radius on a level road if the coefficient of friction between the tyres and the road is 0.4. Take g = 10 ms^(-2) .

Find the force required to move a train of mass 10^(5) kg up an incline of 1 in 50 with an acceleration of 2 ms^(-2) . Coefficient of friction between the train and rails is 0.005. Take g = 10^(2) .

A horizontal force of 1 N is needed to keep a block of mass 0.25 kg sliding on a horizontal surface with a constant speed. The coefficient of sliding friction must be : [take g = 10 ms^(–2) ]