A gramophone disc rotates at 60 rpm. A coin of mass 18 g is placed at a distance of 8 cm from the centre. Calculate the centrifugal force on the coin. Take `pi^(2) = 9.87`.

A gramophone disc rotates at 60 rpm . A coin of mass 18 g is placed at a distance of 8 cm from the centre . Calculate centrifugal force on the coin . Take pi^(2) = 9. 87 .

A gramophone disc rotates with a uniform angular velocity of 6 rad//s . A coins of mass 2 gm is placed 5 cm from the centre .The centripetal force acting on the coin is

A disc starts rotating with a constant angular acceleration of 1 rad//s^(2) about a fixed vertical axis perpendicular to its plane and passing through its centre. A coin of mass 10 gm is placed on the disc at a distance of 10cm from the axis. The coefficent of friction between the disc and the coin is 0.2 . The value of the frictional force on the coin at t=1s will be

A coin kept on a rotating gramophone disc just beging to slip if its centre is at a distance of 8 cm from the centre of the disc .The angular velocity of the gramophone disc is then doubled , Through what distance , the coin should be shifted towards the centre , so that the coin will just slip ?

A coin placed on a rotating gramophone disc, remains at rest when it is at a distance of 9 cm from its centre ,the angular velocity of the disc is then tripled .At what distance from the centre ,the coin should be placed , so that it will remain at rest ?

A small coin of mass 80g is placed on the horizontal surface of a rotating disc. The disc starts from rest and is given a constant angular acceleration alpha=2rad//s^(2) . The coefficient of static friction between the coin and the disc is mu_(s)=3//4 and cofficient of kinetic friction is mu_(k)=0.5 . The coin is placed at a distance r=1m from the centre of the disc. The magnitude of the resultant force on the coin exerted by the disc just before it starts slipping on the disc is

A coin just remains on a disc rotating at a steady rate of 180r.p.m .A coin is kept at a distance of 2 cm from the axis of rotationn . The coefficient of fricition between the coin and the disc is _____ [ gg= 9.8 m//s^(2)]

A coin placed on a rotating turn table just slips if it is placed at a distance of 8 cm from the centre. If angular velocity of the turn table is doubled . It will just slip at a distance of

A small coin of mass 40 g is placed on the horizontal surface of a rotating disc. The disc starts from rest and is given a constant angular acceleration alpha="2 rad s"^(-2) . The coefficient of static friction between the coin and the disc is mu_(s)=3//4 and the coefficient of kinetic friction is mu_(k)=0.5. The coin is placed at a distance r=1m from the centre of the disc. The magnitude of hte resultant force on the coin exerted by the disc just before it starts slipping on the disc is :

A coin placed on a rotating turntable just slips if it is placed at a distance of 16 cm from the centre. If the angular velocity of the turnable is doubled, it will just slip at a distance ( in cm) of