When forces `F_1`, `F_2`, `F_3`, are acting on a particle of mass m such that `F_2` and `F_3` are mutually perpendicular, then the particle remains stationary. If the force `F_1` is now removed then the acceleration of the particle is

When forces F_(1) , F_(2) , F_(3) are acting on a particle of mass m such that F_(2) and F_(3) are mutually prependicular, then the particle remains stationary. If the force F_(1) is now rejmoved then the acceleration of the particle is

When force vec(F)_(1),vec(F)_(2),vec(F)_(3) are acting on a particle of mass m , the particle remains in equilibrium. If the force vec(F)_(1) is now removed then the acceleration of the particle is :

When force vec(F_(1)), vec(F_(2)),vec(F_(3))"…..."vec(F_(n)) act on a particle , the particle remains in equilibrium . If vec( F_(1)) is now removed then acceleration of the particle is

F_1 particles occur in

When a force F acts on a particle of mass m, the acceleration of particle becomes a. now if two forces of magnitude 3F and 4F acts on the particle simultaneously as shown in figure, then the acceleration of the particle is

Five forces vec(F)_(1) ,vec(F)_(2) , vec(F)_(3) , vec(F)_(4) , and vec(F)_(5) , are acting on a particle of mass 2.0kg so that is moving with 4m//s^(2) in east direction. If vec(F)_(1) force is removed, then the acceleration becomes 7m//s^(2) in north, then the acceleration of the block if only vec(F)_(1) is action will be:

A particle of mass m is acted upon by a force F= t^2-kx . Initially , the particle is at rest at the origin. Then

Force acting on a particle of mass m moving in straight line varies with the velocity of the particle as F=K//V K is constant then speed of the particle in time t