Two particles of masses `m_1 and m_2` in projectile motion have velocities `vecv_1 and vecv_2` respectively at time `t=0.` They collide at time `t_0.` Their velocities become `vecv_1' and vecv_2'` at time `2t_0` while still moving in air. The value of `|(m_1vecv_1' + m_2vecv_2') - (m_1vecv_1 + m_2vecv_2)|` is

Two particles of masses m_(1) and m_(2) in projectile motion have velocities vec(v)_(1) and vec(v)_(2) , respectively , at time t = 0 . They collide at time t_(0) . Their velocities become vec(v')_(1) and vec(v')_(2) at time 2 t_(0) while still moving in air. The value of |(m_(1) vec(v')_(1) + m_(2) vec(v')_(2)) - (m_(1) vec(v)_(1) + m_(2) vec(v)_(2))|

Two particles of same mass 'm' moving with velocities vecv_1= vhati, and vecv_2 = (v/2)hati + (v/2)hatj collide in-elastically. Find the loss in kinetic energy

The corresponding quantities in rotational motion related to m, vecF, vecp and vecv in linear motion are respectively

A particle of mass 1 g moving with a velocity vecv_1=3hati-2hatj m s^(-1) experiences a perfectly in elastic collision with another particle of mass 2 g and velocity vecv_2=4hatj-6 hatk m s^(-1) . The velocity of the particle is

In a one-dimensional collision between two particles, their relative velocity is vecv_(1) before the collision and vecv_(2) after the collision

If vecu and vecv are unit vectors and theta is the acute angle between them, then 2 uvecu xx 3vecv is a unit vector for

Two particle of equal mass have velocities vecv_(1)=2hati m/s and vecv_(2)=2hatj m/s. First particle has an accelration veca_(1)=(3hati+3hatj)m//s^(2) while the acceleration of the other particle is zero. The centre of mass of the two particle moved on a