A block of mass 4kg rests on a rough horizontal plane. The plane is gradually inclined until at an angle `theta=60^(@)` , with the vertical, the mass just begins to side. What is the coefficient of static friction between the block and the plane?

A mass of 4 kg rest on a horizontal plane . The plane is gradually inclined until an angle 0 = 15^(@) with the horizontal and the mass just begins to slide . What is the coefficient of static friction between the block and the surface ?

A mass of 4 kg rests on a horizontal plane. When the plane is gradually inclined to an angle 0 -15° with the horizontal, the mass just begins to slide. What is the coefficient of static friction between the block and the surface? [Given, tan 15° = 0.2679)

A block of mass 5 kg rests on a inclined plane at an angle of 30^(@) with the horizontal. If the block just begins to slide, then what is the coefficient of static friction between the block and the surface?

A block is stationary on an inclined plane If the coefficient of friction between the block and the plane is mu then .

A block of mass m lying on a rough horizontal plane is acted upon by a horizontal force P and another force Q inclined at an angle theta to the vertical. The minimum value of coefficient of friction of friction between the block and the surface for which the block will remain in equilibrium is

A block of mass 5 kg is placed on a rough inclined plane. The inclination of the plane is gradually increased till the block just begins to slide down. The inclination of the plane is than 3 in 5. The coefficient of friction between the block and the plane is (Take, g = 10m//s^(2) )

A box of mass 4kg rests upon an inclined plane This inclination is gradually incresed till the box starts sliding down the plane. At this stage slope of the plane is 1 in 3 Find coefficient of friction between the box and the plane What force applied to the box parallel to the plane will just make the box move up the plane ?