A block is stationary on an inclined plane If the coefficient of friction between the block and the plane is `mu` then
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A block of mass m is placed on a rough inclined plane. The corfficient of friction between the block and the plane is mu and the inclination of the plane is theta .Initially theta=0 and the block will remain stationary on the plane. Now the inclination theta is gradually increased . The block presses theinclined plane with a force mgcostheta . So welding strength between the block and inclined is mumgcostheta , and the pulling forces is mgsintheta . As soon as the pulling force is greater than the welding strength, the welding breaks and the blocks starts sliding, the angle theta for which the block start sliding is called angle of repose (lamda) . During the contact, two contact forces are acting between the block and the inclined plane. The pressing reaction (Normal reaction) and the shear reaction (frictional force). The net contact force will be resultant of both. Answer the following questions based on above comprehension: Q. If mu=(3)/(4) then what will be frictional force (shear force) acting between the block and inclined plane when theta=30^@ :

A block of mass m is placed on a rough inclined plane. The corfficient of friction between the block and the plane is mu and the inclination of the plane is theta .Initially theta=0 and the block will remain stationary on the plane. Now the inclination theta is gradually increased . The block presses theinclined plane with a force mgcostheta . So welding strength between the block and inclined is mumgcostheta , and the pulling forces is mgsintheta . As soon as the pulling force is greater than the welding strength, the welding breaks and the blocks starts sliding, the angle theta for which the block start sliding is called angle of repose (lamda) . During the contact, two contact forces are acting between the block and the inclined plane. The pressing reaction (Normal reaction) and the shear reaction (frictional force). The net contact force will be resultant of both. Answer the following questions based on above comprehension: Q. For what value of theta will the block slide on the inclined plane:

A block of mass m is lying on an inclined plane. The coefficient of friction between the plane and the block is mu . The force (F_(1)) required to move the block up the inclined plane will be:-

A block of mass m is placed at rest on an inclination theta to the horizontal.If the coefficient of friction between the block and the plane is mu , then the total force the inclined plane exerts on the block is

A block of mass m=4kg is placed oner a rough inclined plane as shown in figure. The coefficient of friction between the block and the plane is mu=0.5 . A force F=10N is applied on the block at an angle of 30^(@) .

A block of mass m is at rest on a rough inclined plane of angle of inclination theta . If coefficient of friction between the block and the inclined plane is mu , then the minimum value of force along the plane required to move the block on the plane is

A small blockofmass 'm' is released from rest at the top of a rough inclined plane as shown The coefficient of friction between the block and inclined plane is 'mu' Using work-energy theorem, find the speed of block as it passes the lowest point.

A block of mass m rests on a rough inclined plane. The coefficient of friction between the surface and the block is µ. At what angle of inclination theta of the plane to the horizontal will the block just start to slide down the plane?