A soap film is on a rectangular wire ring of size `5cm ** 4 cm`. If the size of the film is changed to `5cm xx 5cm`, then calculate the work done in this process. The surface tension of soap film is `5 xx 10^(-2) Nm^(-1)`.

A soap film in on a rectangular wire of size 4 cm xx 4 cm. If the size of the film is changed to 5 cm xx 5 cm, then calculate the work done in this process. The surface tension of soap film is 6xx10^(-2) Nm^(-1)

A rectangular wire frame of size 2 cm xx 2 cm, is dipped in a soap solution and taken out. A soap film is formed, it the size of the film is changed to 3 cm x 3 cm, Calculate the work done in the process. The surface tension of soap film is 3 xx 10^(-2) N/m.

Calculate the work done in blowing out a soap bubble of diameter 1 cm. given that the surface tension of soap solution is 28 xx 10^(-3) Nm^(-1)

A soap film in formed on a frame of area 4xx10^(-3)m^(2) . If the area of the film in reduced to half, then the change in the potential energy of the film is (surface tension of soap solution =40xx10^(-3)N//m)

The amount of work done in blowing up a soap bubble of radius 2 cm is [Given surface tension of soap solution = 4 xx 10^(-2) N m^(-1) ]

What will be the work done in blowing a soap bubble of radius 1 cm to 2 cm ? (If surface tension of soap solution is 25 xx 10^(-3) N/m)

The work done in forming a soap film of size 10 cm xx 10 cm will be , it if the surface tension of soap solution is 3xx 10^(-2) N/m

A rectangular film of liquid is extended from 5 cm xx 3 cm to 6 cm xx 5 cm . If the work done is 3.0 xx 10^(-4) J . The surface tension of liquid is