Two soap bubbles of unequal sizes are blown at the end of a capillary tube. Which one will grow at the expense of the other end what does it show?

When one end of a capillary tube is dipped vertically in water, the pressure below the meniscus of water is

A soap bubble is blown at the end of a capillary tube of radius a and length L. When the other end is left open, the bubble begins to deflate. Write the radius of the bubble as a function of time if the initial radius of the bubble was R_(0) . Surface tension of soap solution is T. It is known that volume flow rate through a tube of radius a and length L is given by Poiseuille’s equation- Q=(pia^(4)DeltaP)/(8ne L) Where DeltaP is pressure difference at the two ends of the tube and ne is coefficient of viscosity. Assume that the bubble remains spherical.

If two soap bubbles of unequal radii are in communication with each other , then

Two soap bubbles A and B of different diameters are blown at the two ends of a bent tube. By opening the stopcock S , the two bubbles are put in communication. What will happen?

Tow soap bubbles A and B are formed at the two open ends of a tube. The bubble A is smaller then bubble B. If the valve on the tube connecting the two bubbles is opened and air can flow freely between the bubbles, then

Explain why water would completely fill a fine capillary tube which is open at both ends when one end is immersed in water.

The locus of the centre of the cicle for which one end of a diamert is (1.) while the other end is one the line

The soap bubble formed at the end of the tube is blown very slowly. Draw the graph between excess of pressure inside the bubble with time.

In the last problem, one of the bubbles supplies its entire air to the other bubble and a film of soap solution is formed at the end of the straw which keeps it closed. What is the radius of curvature of this film if the bigger bubble has grown in size and its radius has become R_(3) .