An open glass tube is immersed in mercury so that a length of `8 cm` of the tube projects above the mercury. The tube is then closed and raised through `44 cm`. What length of the tube will be occupied by the air after it has been raised? Given `1` atm `= 76 cm` of Hg.

An open glass tube is immersed in mercury in such a way that a length of 8 cm extends above the mercury level. The open end of the tube is then closed and sealed and the tube is raised vertically up by additional 46 cm. what will be length of the air column above mercury in the above now ? (Atmospheric pressure = 76 cm of Hg)

An open glass tube is immersed in mercury in such a way that a length of 8 cm extends above the mercury level. The upon end of the tube is then closed and sealed and the tube is reaised vertically up by additinal 46 cm. What will be length of the air column above mercury in the now? ltbr (atmospheric pressure =76 cm of Hg)

An open glass tube is immersed in mercury in such a way that a lenth of 8cm extends above the mercury level. The open end of the tube is then closed and sealed and the tube is raised vertically up by additional 46cm. What will be length of the air column above mercury in the tube now? (Atmosphere pressure =76cm of Hg)

The lower end of a capillary tube is immersed in mercury. The level of mercury in the tube is found to be 2 cm below the outer level. If the same tube is immersed in water, up to what height will the water rise in the capillary ?

A capillary tube when immersed vertically in a liquid records a rise of 6 cm . If the tube is immersed inclined 30^@ with the vertical , then length of liquid column along the tube will be

An open U-tube contains mercury. When 11.2 cm of water is poured into one of the arms of the tube, how high does the mercury rise in the other arm from its initial level ?