A gaseous mixture enclosed in a vessel consists of one gram mole of a gas A with `gamma=(5/3)` and some amount of gas B with `gamma=7/5` at a temperature T.
The gases A and B do not react with each other and are assumed to be ideal. Find the number of gram moles of the gas B if `gamma` for the gaseous mixture is `(19/13)`.

A gaseous mixture enclosed in a vessel of volume V consists of one mole of a gas A with gamma=(C_p//C_v)=5//3 and another gas B with gamma=7//5 at a certain temperature T. The relative molar masses of the gasses A and B are 4 and 32, respectively. The gases A and B do not react with each other and are assumed to be ideal. The gaseous mixture follows the equation PV^(19//13)=constant , in adiabatic processes. (a) Find the number of moles of the gas B in the gaseous mixture. (b) Compute the speed of sound in the gaseous mixture at T=300K . (c) If T is raised by 1K from 300K, find the % change in the speed of sound in the gaseous mixture. (d) The mixtrue is compressed adiabatically to 1//5 of its initial volume V. Find the change in its adaibatic compressibility in terms of the given quantities.

A gaseous mixture enclosed in a vessel of volume V consists of one gram mole of gas A with gamma = (C_(P))/(C_(V)) = (5)/(3) an another gas B with gamma = (7)/(5) at a certain temperature T . The gram molecular weights of the gases A and B are 4 and 32 respectively. The gases A and B do not react with each other and are assumed to be ideal. The gaseous mixture follows the equation PV^(19//13) = constant , in adiabatic process. Find the number of gram moles of the gas B in the gaseous mixture.

1 mole of a gas with gamma=7//5 is mixed with 1 mole of a gas with gamma=5//3 , then the value of gamma for the resulting mixture is

A mixture of n_1 moles of monoatomic gas and n_2 moles of diatomic gas has gamma=1.5