There are N molecules of a gas in a containter. If this number is increased to 2N, what will be (i) pressure (ii) total energy (iii) rms speed of the gas ?

The rms speed of a gas molecule is

A vessel contains N molecules of a gas at temperature T. Now the number of molecules is doubled, keeping the total energy in the vessel constant. The temperature of the gas is

Initially, the translational rms speed of a molecule of an ideal gas is 463 m/s. The pressure and volume of this gas are kept constant, while the number of molecules is doubled. What is the final translational rms speed of the molecules?

The r.m.s speed of the molecules of an ideal gas Is V_0 If pressure of the gas is halved but temperature is kept constant then r.m.s. speed of the gas molecule will be

The rms speed of the molecules of a gas in a vessel is 400ms^(-1) . If half of the gas leaks out at constant temperature, the rms speed of the ramaining molecules will be…………..

The rms speed of the molecules of a gas in a vessel at 80^(@)C is 200m//s . If 40% of the gas is taken out of the vessel, what is the rms speed of the remaining molecules if their temperature is not changed?

The rms speed of N_(2) molecules in a gas in u . If the temperature is doubled and the nitrogen molecules dissociate into nitrogen atom, the rms speed becomes

The mass of molecule A is twice the mass of molecule B. The rms speed of A is twice the rms speed of B. If two samples of A and B contain same number of molecules. If the pressure of gas B is 2atm then what will be the pressure of gas A ( atm) . If two samplest are taken in separate containers of equal volume ?

The distribution of speeds of molecules of a gas depends on (i) temperature , (ii) volume (iii) pressure , (iv) molecular mass