Estimate the average thermal energy of a helium atom at room temperature `(27^(@)C)`. Boltzmann constant `=1.38 xx 10^(-23) JK^(-1)`

Estimate the average thermal energy of a helium atom at (i) room temperature (27^(@)C) . Boltzmann constant =1.38 xx 10^(-23) JK^(-1)

The pressure exerted by an ideal gas is P = (1)/(3) (M)/(V)C^(2) , where the symbols have their usual meaning. Using standard gas equation, PV = RT, we find that C^(2) = (3 RT)/(M) or C^(2) oo T . Average kinetic energy of translation of one mole of gas =(1)/(2) MC^(2) = (3 RT)/(2) with the help of the passage given above, choose the most appropriate alternative for each of the following quetions : Average thermal energy of a helium atom at room temperature (27^(@)C) is Given, Boltzmann constant k = 1.38 xx 10^(-23) JK^(-1) :

The average thermal energy of oxygen at a temperature of 27^(0)C is

Estimate the average thermal energy of a helium atom at (i) room temperature (27^(@)C) (ii) the temperature on the surface of the sun (6000K), (iii) the temperature of 10 million kelvin (the typical core temperature in the case of a car)

Estimate the average energy of a helium atom at (i) room temperature (27^(@)C) (ii) the temperature on the surface of the sun (6000 K) and (iii) the temperature of 10^(7)K . Given k_(B) = 1.38 xx 10^(-23) J "molecule"^(-1) K^(-1)

Calculate the average momentum of a hydrogen molecule at 20^(@)C . Boltzmann constant =1.38xx10^(-23) JK^(-1) and mass of a hydrogen molecule =3.2xx10^(-27)kg .

Estimate the total number of air molecules (inclusive of oxygen, nitrogen, water vapour and other constituents) in a room of capacity 25.0 m^(3) at a temperature of 27^(@) C . And 1 atm pressure. (Boltzmann constant = 1.38 xx 10^(-23) JK^(-1)) .

Calculate the kinetic energy of one mole of argon at 127^(@)C . Given,Boltzmann's constant, k_(B) = 1.381 xx 10^(-23) J "molecular"^(-1) K^(-1) . Avogardro numbe, N = 6.02 xx 10^(23) "mol"^(-1)

Calculate kinetic energy of a gram molecule of oxygen at 127^(@)C . Value of Boltzmann constant = 1.381 xx 10^(-23) J K^(-1) . Avogardro's number = 6.022 xx 10^(23) per gm-mole.

The value closest to the thermal velocity of a helium atom at room temperature (300 K) in ms^(-1) is :[ k_(B)=1.4xx10^(-23) j//k, m_(He)=7xx10^(-27) kg]