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The acceleration of a particle performin...

The acceleration of a particle performing SHM is`12 cm //s^(2)` at a distance of 3 cm from the mean position . Calculate its time - period .
Hint `: a = omega^(2) x`
`a = 12 cm//s^(2) , x=3cm`
Find `omega`
`T= (pi)/(omega)`

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