A weighted glass tube is floating in a liquid with 20cm of its length immresed. It is pushed down through a certain distance and then released. Show that up and down motion executed by the glass tube is SHM and find the time period of vibration. Given `g=980cm s^(-2)`.

A pole is floating in a liquid with 80 cm of its length immersed. It is pushed doun a certain distance and then released. Time period of vertical oscillation is

A glass tube is floating in a liquid with 30 cm of its length immersed in the liquid. If the glass tube is pushed down and released, then calculate the time period of vibration of glass tube.

A vertical U-tube of uniform cross-section contains water upto a height of 2.45 cm. show that if the water on one side is decpressed and then released, its up and down motion in the tube is SHM and calculate its time period. Given g=980cms^(-2) .

A vertical U tube of uniform cross-section contains water up to a heigth of 0.5m . If water on one side is depressed a little and then released its motino up and down the two sides of the tube is SHM. Calculate (i) time period (ii) angular grequency of vibration. g=10ms^(2) .

A vertical U-tube of uniform cross-section contains water upto a height of 30 cm. show that if the water in one limb is depressed and then released, its up and down motion in the two limbs of the tube is simple harmonic and calculate its time-period.

A cubical body (side 0.1m and mass 0.002kg) floats in water. It is pressed and then released so that it executes SHM. Find the time period. (g=10m//s^(2))

If the length of a seconds pendulum is first decreased by 10 cm and its time period is determined and then increased by 20 cm and the time period is once again determined, find the ratio of the time periods in two cases. (Take g = 9.8 m s^(-2) )