Write the values of amplitude and frequency from the equation `y = A sin omega t` of S.H.M.

Write the values of amplitude and angular frequency for the following simple harmonic motion. y = 0.2sin(99 t + 0.36)

A simple harmonic oscillation is represented by the equation. y=0.40sin(440t+0.61) Here y and t are in m are s respectively. What are the values of (i) amplitude (ii) angular frequency (iii) frequency of oscillations (iv) time period of oscillations and (v) initial phase?

The displacement of a represnted by the equation y = sin^(2) omega t the motion is

The differential equation, obtained on eliminating A and B from the equations y= A cos omega wt+ B sin omega t is

Y= 2A cos^(2) (kx - omega t) represents a wave with amplitude A´ and frequency f. The value of A´ and f are:

Find the resultant amplitude of the following simple harmonic equations : x_(1) = 5sin omega t x_(2) = 5 sin (omega t + 53^(@)) x_(3) = - 10 cos omega t

What is the amplitude of the S.H.M. obtained by combining the motions. x_(1)=4 "sin" omega t cm, " " x_(2)=4 "sin"(omega t + (pi)/(3)) cm

A simple harmonic wave having an amplitude a and time period T is represented by the equation y = 5"sin"pi(t + 4)m . Then the value of amplitude (a) in (m) and time period (T) in second are

Find the amplitude and initial phase of a partical in SHM, whose motion equation is given as y = A sin omega t + B cos omega t

The amplitude of a wave represented by displacement equation y=(1)/(sqrt(a)) sin omega t +-(1)/(sqrt(b)) cos omega t will be