Write the values of amplitude and angular frequency for the following simple harmonic motion. `y = 0.2sin(99 t + 0.36)`

Write the values of amplitude and frequency from the equation y = A sin omega t of S.H.M.

A simple harmonic oscillation is represented by the equation. y=0.40sin(440t+0.61) Here y and t are in m are s respectively. What are the values of (i) amplitude (ii) angular frequency (iii) frequency of oscillations (iv) time period of oscillations and (v) initial phase?

Assertion : We can call circular motion also as simple harmonic motion. Reason : Angular velocity in uniform circular motion and angular frequency in simple harmonic motion have the same meanings.

Write the equation for a particle in simple harmonic motion with amplitude a and angular frequency epsilon considering all distance from one extreme position and time when its is at the other extreme position.

A particle executing simple harmonic motion with an amplitude A and angularr frequency omega . The ratio of maximum acceleration to the maximum velocity of the particle is

Write the displacement equation representing the following conditions obtained for a simple harmonic motion: amplitude=0.01m, frequency=600Hz initial phase =pi//6

The resultant amplitude due to superposition of three simple harmonic motions x_(1) = 3sin omega t , x_(2) = 5sin (omega t + 37^(@)) and x_(3) = - 15cos omega t is

The maximum velocity of a simple harmonic motion represented by y= 3 sin (100 t + pi/6 ) is given by

A particle is subjected to two simple harmonic motions in the same direction having equal amplitude and equal frequency. If the resultant amplitude is equal to the amplitude of individual motions, what is the phase difference between the motions.