If on going up a hill, the value of g decreases by 10%, then what change must be made in the length of a pendulum clock in order to obtain accurate time ?

When a pendulum clock gains time, what adjustiment should be made?

If a simple pendulum is taken to place where g decreases by 2%, then the time period

What is the percentage change in the time period, if the length of simple pendulum increases by 3% .

If the length of seconds pendulum is decreased by 1%, the gain or lose time per day by the pendulum will be

If the length of a simple pendulum is doubled then the % change in the time period is :

The time period of a simple pendulum is given by T = 2pisqrt(l/g) . The measured value of the length of pendulum is 10 cm known to a 1 mm accuracy. The time for 200 oscillations of the pendulum is found to be 100 second using a clock of 1 s resolution. The percentage accuracy in the determination of 'g' using this pendulum is 'x'. The value of 'x' to the nearest integer is,

If the percentage decrease in the length of a simple pendulum is 10%, then find the percentage decrease in its time period

If the length of a correct pendulum clock is raised by 0.1% , what will be the effect on the time of the clock in a day ?