A simple pendulum is described by `a = -16x` , where a is acceleration, x is displacement in meter. What is the time period ?

A vibrating simple pendulum of period T is placed in a lift which is accelerating upwards. What will be the effect on the time period?

A vibrating simple pendulum of period T is placed in a lift which is accelerating downwards. What will be the effect on the time period?

The equation of motion of a particle executing simple harmonic motion is a+16pi^(2)x = 0 In this equation, a is the linear acceleration in m//s^(2) of the particle at a displacement x in meter. The time period in simple harmonic motion is

The period of a simple pendulum inside a stationary lift is T. The lift accelerates upwards with an acceleration of g/3 . The time period of pendulum will be

A simple harmonic motion of acceleration 'a' and displacement 'x' is represented by a+4pi^(2)x = 0 What is the time period of S.H.M ?

The time period and the amplitude of a simple pendulum are 4 seconds and 0.20 meter respectively. If the displacement is 0.1 meter at time t=0, the equation on its displacement is represented by :-

A simple pendulum makes 20 oscillations in one second on the surface of the earth. Determine the time period of the simple pendulum on the surface of a planet where the acceleration due to gravity is one fourth of the acceleration due to gravity on the surface of the earth .

If at any time, the displacement of a simple pendulum be 0.02 m, then its acceleration is 2 m/ s^2 . What is the angular speed of the pendulum at that instant?